Complete Study Material | CBSE Board Exam Preparation
Consecutive differences: 4-2=2, 6-4=2, 8-6=2.
Difference is constant.
Final: Yes, AP with d=2.
Differences: 4,4,4.
Final: AP, d=4.
Differences: 4,6,8 (not same).
Final: Not an AP.
Differences: -4,-4,-4.
Final: AP, d=-4.
Each difference is 0.
Final: AP, d=0.
a=2, d=3, n=10.
Formula: a_n=a+(n-1)d.
a_10=2+9*3=2+27=29.
Final: 10th term = 29.
a=7, d=3.
a_15=7+14*3=49.
Final: 15th term = 49.
a=3, d=5.
a_n=3+(n-1)5=78.
5n-2=78 => 5n=80 => n=16.
Final: 78 is the 16th term.
a=11, d=-3.
a_n=11+(n-1)(-3)=11-3n+3=14-3n.
Final: a_n = 14 - 3n.
a=6, d=7.
6+(n-1)7=100 => 7n-1=100 => 7n=101.
n is not integer.
Final: 100 is not a term of this AP.
a=3, d=4, n=20.
S_n=n/2[2a+(n-1)d].
S_20=20/2[6+19*4]=10[6+76]=820.
Final: S_20 = 820.
AP: 1,2,3,...,30 so a=1, l=30, n=30.
S_n=n/2(a+l)=30/2(31)=15*31=465.
Final: 465.
AP: 1,3,5,... with a=1, d=2, n=25.
S_25=25/2[2+24*2]=25/2(50)=625.
Final: 625.
a=5,d=3.
S_n=n/2[10+3(n-1)] = n/2(3n+7)=405.
n(3n+7)=810 -> 3n^2+7n-810=0.
Factor: (n-15)(3n+54)=0.
Final: n = 15.
Given S_n=n^2+2n.
a_n=S_n-S_(n-1).
S_(n-1)=(n-1)^2+2(n-1)=n^2-1.
a_n=(n^2+2n)-(n^2-1)=2n+1.
So terms are 3,5,7,9,...
Final: AP is 3, 5, 7, 9, ...